Question

A car of of mass 480 kg moving at a speed of 54 km per hour is stopped by applying brakes in 10 second calculate the force applied by the brakes

Answer 1

M= 480 kg
u= 54km/hr×5/18= 15m/s
v=0
t=10s

Force= kma
=k (m (v-u))/t (k's value is 1)
=1(480 (-15)/10)
=48*-15= -720kgm/s^2
= -720N
Please mark as the brainliest answer :)

Answer 2

Answer:given:

M= 480 kg

u= 54km/hr×5/18= 15m/s

v=0

t=10s

Force= kma

=k (m (v-u))/t (k's value is 1)

=1(480 (-15)/10)

=48*-15= -720kgm/s^2

= -720N

Explanation: