Question

a car on the cross road is moving towards east at a speed of 40km /hr . another car which is 1 km south of the crossing is approaching the crossing with the same speed . thear closest distance of approaching will be​

Answer 1

Answer:

Their closest distance of approaching will be​  1/√2 km

Explanation:

The car is moving towards east at the speed of 40 km/hr

Let the speed of the car is a1,

then a1= 40 km/hr

Another car is moving towards south at the speed of 40 km/hr

Let the speed of the car is a2,

then a2= 40 km/hr

The distance between these two cars are of 1 km.

The angle between these two cars is

tanθ= a1/a2

or, θ= tan^(-1)a1/a2

or, θ= tan^(-1)40/40

or, θ= tan^(-1)(1)

or, θ= 45°

As we all know to find the shortest distance the method is,

distance s= xsinθ

                 = 1 x sin 45° [ where x= 1 km]

                  = 1 x 1/√2

                  = 1/√2 km