Question

a car posses avg velocities of 5ms,10ms,15ms in first , second, third seconds wt is the total distanceby the car covered by the car in these 3 seconds

Answer 1

30 m
Taking the case of constant acceleration in parts with constant average velocity gives the same answer.
So the distance travelled in 1st second = 5 m
Distance travelled in 2nd second = 10 m
Distance covered in 3rd second = 15 m
Which makes the total distance travelled = 5m + 10m + 15m = 30 m.

Answer 2

30 m
Taking the case of constant acceleration in parts with constant average velocity gives the same answer.
So the distance travelled in 1st second = 5 m
Distance travelled in 2nd second = 10 m
Distance covered in 3rd second = 15 m
Which makes the total distance travelled = 5m + 10m + 15m = 30 m.

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