Question

a car racing has a circular lap and the organiser to hold both to 23400 metres and 43200 using the same lap .
what should be the circumference of the circular lap so that both the races start and finish at the same point​

Answer 1

Step-by-step explanation:

Given  

a car racing has a circular lap and the organiser to hold both to 23400 metres and 43200 using the same lap . what should be the circumference  of the circular lap so that both the races start and finish at the same point​

We need to find circumference of a circle. They have given 23400 and 43200. We have to find the greatest common multiple.So factors are

1. 23,400 = 2 x 2 x 2 x 3 x 3 x 5 x 5 x 13

2. 43,200 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 5 x 5

So the common factors are 2 x 2 x 2 x 3 x 3 x 5 x 5

                                            = 72 x 25

                                         = 1800

So the circumference of the circle will be 1800 m