Question

a car requires a velocity of 72km/h in 10 seconds starting from rest. find acceleration, average velocity, distance in time

Answer 1

hey here is your answer

Answer 2

Given that,

Time,t = 10s
the primary velocity = 0 {The car was in rest}
The final velocity = 72 km\h = 20 km\s

We know,

a= (v-u)\t
=> (20-0)\10
=> 2 m\s²
Again,
Distance, s = ut + 0.5× at²
=> 0 + 0.5 ×2×10²
=> 100 m

Average velocity = (v+u)\2
=> (20+0)\2
=> 10m\s

Hi friends! Here is ur answer.. :)