Question

a car running 65 km/h takes one hour to cover a distance. if the speed is reduced by 15 km/hour then in how much time it will cost of car is
a)72 mins
b) 78 mins
c ) 76 mins
d) None of these​

Answer 1

Answer:

d

L.H.S. = x2 – y2

= (p sec θ + q tan θ)2 – (p tan θ + q sec θ)2

= p2 sec θ + q2 tan2 θ + 2 pq sec 2 tan 2 -(p2 tan2 θ + q2 sec2 θ + 2pq sec θ tan θ)

= p2 sec θ + 2 tan2 θ + 2pq sec θ tan θ – p2 tan2 θ – q2 sec θ – 2pq sec θ tan θ

= p2(sec2 θ – tan2 θ) – q2(sec?2 θ – tan2 θ) =

= p2 – q2 …[sec2 θ – tan2 θ = 1

= R.H.S.hii

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Answer 2

Answer:

correct answer is option: B

Step-by-step explanation:

First determine the distance. Its traveling at 65 for an hour so:

(65 km/h) *1h = 65 km

Divide the same distance by the new speed (65–15) to get time.

65km/(65–15)km/hour = 1.3 hours ,I.e 78 minutes