Question

a car runs at 5m/s in east direction and takes a sharp turn and continue at 5m/s find the changes in velocity​

Answer 1

0 (zero).

Since, (final velocity - initial velocity) = 0

i.e., (5-5) m/s

= 0 m/s.

Sorry if incorrect.

Hope it helped.

Answer 2

Answer:

actually the correct answer is 5√2

Explanation:

Change in velocity= v2-v1

= V2+(-v1)

so use the formula

R= 2v×sin(theta)/2

R= 2×5 ×90/2

R= 5√2