A car speed is 90kmph and it get decrease to 36kmph in 5 sec so how much distance the car covered in 5 sec
Mayur1910:
Give me answer plz
Elaborate plz how we get u and v
Plz
u is initial velocity which is given in question as 90kph
v is final velocity which is given in questions as 36kph
Since they are in kph so convert them by multiplying by 5/18
v=u+at______FIRST LAW OF MOTION
Therefore a=v-u/t
Thank
Answers
Answered by
1
a=v-u/t
54/5=3m/s^2
s=ut+1/2(at^2)
s=125-75/2
=125-37.5
=82.5m
54/5=3m/s^2
s=ut+1/2(at^2)
s=125-75/2
=125-37.5
=82.5m
Only applicable for velocity
So Sorry
90*5/18=25mps
36*5/18=10mps
25-10/5=3mps^2
Thats the actual method
I did it in short by simply converting acceleration from kmph^2 to mps^2
Welcome and plz maek as brainliest
Thank you and explain 3 line detail as s=125-75/2
Accept my frnd request i will explain in detail in pesonal chat
Answered by
0
90 kmph = 90 * 5/18 m/s = 25 m/s
36 kmph = 36 * 5/18 m/s = 10 m/s
a = (v - u) / t
= (10 - 25) / 5
= -3 m/s^2
S = ut + 0.5at^2
= 25*5 + 0.5*(-3)*5^2
= 87.5 m
Distance travelled by car in 5s is 87.5 m
36 kmph = 36 * 5/18 m/s = 10 m/s
a = (v - u) / t
= (10 - 25) / 5
= -3 m/s^2
S = ut + 0.5at^2
= 25*5 + 0.5*(-3)*5^2
= 87.5 m
Distance travelled by car in 5s is 87.5 m
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