Question

A car speeds up from 12 m/s to 20 m/s in 6.4 s. If its mass is 1200 kg, what force must its engine provide?

Answer 1

Answer:

Explanation:

F=ma

m=mass of car=1200 kg

a=acceleration of car

u, initial speed = 12 m/s

v,final speed =20 m/s

t,time taken to achieve final speed= 6.4 secs

a=v-u/t=8/6.4 m/s^2

Force to be provided

F= 1200*8/6.4 N

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Answer 2

Answer:

Given that,

u=12m/s,v=20m/s

Time,t=6.4s

From the first law of motion,

V=u+at

20=12+6.4a

6.4a=8

a=80/64=5/4m/s²

Now,F=ma

F=1200×1000/5/4

F=1200×1000×4/5

F=960×10³N

Explanation:

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