A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find
(i) the acceleration
(ii) distance travelled by car assume motion of car is uniform?
answer
Answers
Answer:
1) acceleration = 7.5m/s²
2) distance travelled = 15m
Explanation:
Given that a car starts from rest
so,
initial velocity will be 0
in 2 seconds it acquires a velocity of 54km/h
= 54000m/3600s
= 540m/36s
15m/s
so,
now, it's given that
initial velocity(u) = 0m/s
final velocity(v) = 15m/s
time(t) = 2 s
so,
acceleration = v - u
t
= 15/2 m/s²
= 7.5m/s²
now,
if motion is uniform
then distance(s) travelled in 2 seconds =
s = ut + 1/2at²
= 0×2 + 1/2 × 7.5 × 2 × 2
= 15m
Answer: acceleration = 7.5m/s2
distance travelled = 15m
Explanation:
Given that
Initial velocity, u = 0m/s
Final velocity,v = 54 km/ h
=15m/s
time, t = 2 sec.
we know that
a = v - u/ t
= 15 - 0 / 2
=15/2
=7.5m/s2
then distance travelled,
s = ut + 1/2 *at2
= 0*2 + 1/2* 7.5*2*2
=15m
HOPE IT HELPS YOU!