Question

A car start from rest and acquire a velocity of 54km\h in 2sec. find
(a) the acceleration
(b) distance travelled by car assume motion of car is uniform ?

Answer 1

Car starts from rest so u = 0
V = 54 km/hr = 54*5/18 = 15m/s
t = 2sec
a)
Using, V = u + at
15 = 0 + a*2
a = 15/2 = 7.5 m/s^2

b) distance travelled, s
S = ut + 1/2 a ^2
S = 0 + 1/2 * 15/2 * 2 * 2 = 15m

Answer 2

HOLA!!

HERE YOUR ANSWER IS

GIVEN

initial velocity (u) = 0 (since started from rest )

final velocity (v) = 54km/h = 54000/3600 m/s

time (t) = 2 s

acceleration =?

distance= ?

SOLUTION

a) acceleration = change in velocity /time

= (v-u)/t

= (54000 -0)/2×3600

= 54000 /7200

= 7.5 m/s^2

b) Remember we can find distance by

s = ut+1/2at^2

= 0 (2)+1/2 (7.5)(2)^2

= 0 +1/2 (7.5)(4)

= 1/2 (30)

= 15 m

HOPE IT HELPS YOU