Question

a car start from rest and moves Along X Axis with constraints acceleration 5meter per second square from 8 sec if than continue with constraints velocity what distance will car cover in 12 sec since it started from rest​
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Answer 1

Let's do one the warm into 2 parts..

1) The distance is travelled into next 8 sec i.e in total 12sec.

2) The distance travelled into the next 4 sec i.e In total 12 sec.

Given,

u = 0

a = 5m/s^2

t = 8 sec.

Using the eq. s = ut+1/2at^2

s = 0+(1/2)*5*8^2

s = 160m.......... This is the distance travelled in 8 sec.

Now while considering the 2nd part the final velocity in the first becomes the initial in the sec.

Find the final velocity = v = u+at

U get v = 40m/s

In the second part it is said that the body moves with uniform velocity i.e a = 0

Using the eq. s = ut+1/2at^2

U get s = (40*4)+0

s = 160

Therefore the total distance travelled = 160+168

= 320m

.....plzzz mark the answer as brainliest