a car starting from rest acquires a speed 25 m/s in 10 sec.after which it maintains this speed for 10 sec. find(a) the acceleration (b) distance travelled during acceleration (c) total distance travelled?
Answers
u = 0 m/s
v = 25 m/s
t = 10 m/s
a) a = ?
As v = u + a t
so, 25 = 0 + a * 10
so, a = 25/10 = 2.5 m/s^2
b) s = ? (for first 10 s)
As s = ut + 1/2 a t^2
so, s = 0 + 1/2 * 2.5 * 10^2
so. s = 125 m
c) s = ? ( for next 10 s)
s = v * t as a = 0 m/s^2
so, s = 25*10
so, s = 250 m
Hnce, total distnce = 125 + 250
= 375 m
Answer:
a) acceleration is 2.5
b) distance during acceleration 125 m
c) total distance 375 m
Explanation:
GIVEN:
initial speed
final speed
time taken
Determining a) Acceleration a in
acceleration is given by equation as given below:
substituting value in above equation
Determining b) distance travelled during acceleration, lets say it be s
Substituting value in equation
Determining c) total distance travelled, be d
Lets say y is distance travelled through uniform motion
Now adding them together gives d