A car starting from rest acquires a velocity of 36km/h in 5 seconds. Calculate the distance covered by it.
Answers
Answered by
11
given,
u = 0
v = 10 m/s
t = 5 S
then, a = v - u ÷ t
= 10 - 0 ÷ 5
= 2 m / S ^ 2
S = ut + 1/2 at^2
= 0+ 1/2 *2 * 5*5
= 5*5
= 25 m
u = 0
v = 10 m/s
t = 5 S
then, a = v - u ÷ t
= 10 - 0 ÷ 5
= 2 m / S ^ 2
S = ut + 1/2 at^2
= 0+ 1/2 *2 * 5*5
= 5*5
= 25 m
Answered by
0
Answer:
Look at the explanation
Attachments:
Similar questions