a car starting from rest acquires the velocity of 54 km per hour in 5 seconds calculate (1) its acceleration and (2) distance moved by it
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Answered by
30
HEY BUDDY..!!!
HERE'S THE ANSWER..
________________________
⏺️A car starting from rest means it's initial velocity is 0 , i.e u = 0
=> v ( final velocity ) = 54 km / h = 54 × 1000 / 3600 m /s
=> v ( final velocity ) = 15 m /s
=> t = 5 second
So ,
( a )
=> a = v - u / t
=> a = 15 / 3
=> 3 m / s^2
( b )
=>s = u × t + 1 / 2 a × t^2
=> s = 1 / 2 a × t^2
=> s = 1 / 2 × 3 × 25
= 37.5 m
HOPE IT HELPS..
HAVE A NICE DAY..
:-)
HERE'S THE ANSWER..
________________________
⏺️A car starting from rest means it's initial velocity is 0 , i.e u = 0
=> v ( final velocity ) = 54 km / h = 54 × 1000 / 3600 m /s
=> v ( final velocity ) = 15 m /s
=> t = 5 second
So ,
( a )
=> a = v - u / t
=> a = 15 / 3
=> 3 m / s^2
( b )
=>s = u × t + 1 / 2 a × t^2
=> s = 1 / 2 a × t^2
=> s = 1 / 2 × 3 × 25
= 37.5 m
HOPE IT HELPS..
HAVE A NICE DAY..
:-)
Answered by
1
Answer:
use the formula a= v-u /T
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