Question

A car starting from rest and moving along a straight
path with uniform acceleration covers distances p
and q in the first two successive equal intervals of
time. Find the ratio of p to q.​

Answer 1

Explanation:

please mark it brainliest answer,.....

Answer 2

Answer:

let the time intervals be "t" second each and the distances covered after t second and 2t be x1 and x2 respectively. ( don't take the 1 and 2 as powers they are subscripts here).

then from the 2nd equation of motion, since intial velocity is 0 (i.e U=0),so

x1=(1/2)*

${at}^{2}$

=1/2 a (t^2)

and, ×2=(1/2)*a (2t) square

where a is the constant acceleration

so, P

=1/2 a (t^2)

and q=2a(t^2)-1/2 a (t^2)=3/2 a (t^2)

so, p/q=1/3