Physics, asked by ashley8474, 1 month ago

a car starting from rest and picks up a velocity of 20 km per hour in 10 second calculate acceleration of a car... (chang the km to mtrs)​

Answers

Answered by MystícPhoeníx
98

Answer:

  • -0.55 m/s² is the required acceleration.

Explanation:

Given:-

  • Initial velocity ,u = 20km/h = 20× 5/18 = 100/18 = 5.5m/s
  • Final velocity ,v = 0m/s
  • Time taken ,t = 10 s

To Find:-

  • Acceleration ,a ?

Solution:-

We have to calculate the acceleration of the car . As we know that acceleration is defined as the rate of change of velocity at per unit time .

a = v-u/t

where,

  • v is the final velocity
  • a is the acceleration
  • u is the initial velocity
  • t is the time taken

Substitute the value we get

➺ a = 0-5.5/10

➺ a = -5.5/10

➺ a = -0.55 m/s²

here ,

negative sign show retardation

  • Hence, the acceleration of the car is -0.55m/s.

Answered by Anonymous
90

Answer:

Correct Question :-

  • A car starting from rest and picks up a velocity of 20 km/h in 10 seconds. Calculate the acceleration of a car.

Given :-

  • A car starting from rest and picks up a velocity of 20 km/h in 10 seconds.

To Find :-

  • What is the acceleration of a car.

Formula Used :-

\clubsuit Acceleration Formula :-

\longmapsto \sf\boxed{\bold{\pink{a =\: \dfrac{v - u}{t}}}}\\

where,

  • a = Acceleration
  • v = Final Velocity
  • u = Initial Velocity

Solution :-

\bigstar Final Velocity :-

\implies \sf\bold{\green{0\: m/s}}

\bigstar Initial Velocity :

\implies \sf 20\: km/h

\implies \sf 20 \times \dfrac{5}{18}\: m/s

\implies \sf \dfrac{100}{18}\: m/s

\implies \sf\bold{\green{5.55\: m/s}}

\bigstar Time Taken :

\implies \sf\bold{\green{10\: seconds}}

Hence, we get :

  • Initial Velocity = 5.55 m/s
  • Final Velocity = 0 m/s
  • Time Taken = 10 seconds

According to the question by using the formula we get,

\dashrightarrow \sf a =\: \dfrac{0 - 5.55}{10}

\dashrightarrow \sf a =\: \dfrac{- 5.55}{10}

\dashrightarrow \sf a =\: \dfrac{- 555}{10 \times 100}

\dashrightarrow \sf a =\: \dfrac{- 555}{1000}

\dashrightarrow \sf\bold{\red{a =\: - 0.555\: m/s^2}}

\therefore The acceleration of a car is - 0.555 m/.

[Note : The negetive (- ve) signs indicate the velocity is decreasing. ]

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