Question

a car starting from rest at a speed of 20 metre per second in covering a distance of hundred metre calculate the acceleration​

Answer 1

Answer:

✬ Acceleration = 2 m/s² ✬

Explanation:

Given:

A car starting from rest (u) = 0 m/s

Car acquires the final speed (v) after starting= 20 m/s

Distance (s) covered by the car = 100 m.

To Find:

What is the acceleration (a) of the car ?

Formula to be used:

Newton's third law of motion

v² = u² + 2as

Solution: Let the acceleration of car be a. Putting the given values on formula

v² = u² + 2as

(20)² = (0)² + 2 a 100

400 = 0 + 200a

400 = 200a

400/200 = a

2 m/s² = a

Hence, the acceleration of the car is 2 m/s².

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★ Other laws of motion ★

➱ v = u + at ( First law )

➱ v = u + 1/2at² ( Second law )

➱ V = Final Velocity :- The distance covered by an object in a given period of time.

➱ U = Initial Velocity :- The velocity of an object before the acceleration causes a change into it.

➱ T = Time

Answer 2

Answer:

$2m {s}^{ - 2}$

Explanation:

use the equation

${v}^{2} - {u}^{2} = 2as$

here v = 20

u = 0

s = 100

after solving we get a =2