Question

A car starting from rest moves on a road in straight line accelerates at constant rate of 3 m s -2 for 8 seconds how far does the car travel during this time​

Answer 1

$u = 0 \: {ms}^{ - 1} \\ a = 3 \: {ms}^{ - 2} \\ t = 8 \: sec$

Now,

$s = ut + \frac{1}{2} {at}^{2} \\ \\ \: \: \: = (0 \times 8) + \frac{1}{2} (3 \times {(8)}^{2} ) \\ \\ \: \: \: = \frac{1}{2} \times 3 \times 64 \\ \\ \: \: \: {\red {= 3 \times 32 =96 \: m }}$

Hence,

${ \red{ \boxed{ \textbf{Car \: \: travels \: \: 96 \: m \: \: during \: \: this \: \: time.}}}}$

Answer 2

Answer:

96 m

Explanation:

Given

initial velocity=0 m/s

acceleration=3m/s²

time=8 sec

By 2nd equation of motion

s=ut+1/2at²

=0*8+1/2*3*(8)²

=0+3/2*64

=3*32

=96 m