Question

A car starts at rest and begins to speed up with an acceleration of 1.7 m/s². What distance (in meters) does this car cover in 5.0 seconds?
(-it's kinematics)
(and plz give me a formula for distance.)
Also, the answer is not 130, or speed x time.

Answer 1

Given :

• initial velocity = 0 m/s

• acceleration = 1.7 m/s²

• time = 5 seconds

To find :

• distance covered by the car.

Formula used :

$s = ut + \dfrac{1}{2} a {t}^{2}$

where :

• s = distance
• u = initial velocity
• a = acceleration
• t = time

Solution :

initial velocity = 0 m/s

acceleration = 1.7 m/s²

time = 5 seconds

$\implies \: s = ut + \dfrac{1}{2} a {t}^{2}$

$\implies \: s = (0 \times 5)+ ( \dfrac{1}{2} \times 1.7 \times {5}^{2} )$

$\implies \: s = 0+ ( \dfrac{1}{2} \times 1.7 \times {5}^{2} )$

$\implies \: s = ( \dfrac{1}{2} \times \dfrac{17}{10} \times {25} )$

$\implies \: s = ( \dfrac{17 \times 25}{2 \times 10} )$

$\implies \: s = \dfrac{425}{20}$

$\implies \: s = 21.25m$

Answer :

• distance = 21.25 metres

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$\implies \: v = u + at$

$\implies \: s = ut + \dfrac{1}{2} a {t}^{2}$

$\implies \: {v}^{2} - {u}^{2} = 2as$

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