A car starts from rest after 10s it attains a velocity of 20m/s calculate acceleration and distance travelled
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Answered by
7
a = v/t
= 20 / 10
= 2 m/s^2
S = 0.5at^2
= 0.5 * 2 * 10^2
= 100 m
Acceleration of car = 2 m/s^2
Distance covered by car = 100 m
= 20 / 10
= 2 m/s^2
S = 0.5at^2
= 0.5 * 2 * 10^2
= 100 m
Acceleration of car = 2 m/s^2
Distance covered by car = 100 m
Answered by
3
@:-)
a = v-u / t
a = 20-0 / 10
a = 20/10
a = 2 m/s²
s = ut+1/2at²
s = 0×10 + 1/2 × 2 × (10)²
s = 0 + 100
s = 100 metre
@:-)
a = v-u / t
a = 20-0 / 10
a = 20/10
a = 2 m/s²
s = ut+1/2at²
s = 0×10 + 1/2 × 2 × (10)²
s = 0 + 100
s = 100 metre
@:-)
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