Question

A car starts from rest and accelarates uniformly over time of 5.21 sec for distance of 110 m determine acceleration of car

Answer 1

Answer:

8.10 m/s^2

Explanation:

According to the given question,

u = initial velocity = 0 m/s

Here distance is equal to the displacement of the car, as it's a linear motion without changing its direction.

So we can use 110 m as displacement too.

s = displacement = 110 m

t = time = 5.21 sec

a = acceleration

And we are asked to find the acceleration of the car.

We know,

• s = ut+ 1/2 × a×t^2

Putting the values we get,

• 110 = 0 + 1/2 × a × 27.14

• 27.14 × a = 220

• a = 220/27.14

• a = 8.10 m/s^2

Thus acceleration of the car after 5.21 sec is 8.10 m/s^2 for 110 m of distance.

Answer 2

☞ A car starts from rest.

Means initial velocity is 0 m/s.

☞ And accelerates uniformly over the time of 5.21 sec for the distance of 110 m.

• Here..

time (t) = 5.21 sec

distance (s) = 110 m

☞ We have to find acceleration (a).

• We know that

=> s = ut + $\dfrac{1}{2}$ at²

• Now put the given values.

=> 110 = 0 × 5.21 + $\dfrac{1}{2}$ × a (5.21)²

=> 110 = $\dfrac{1}{2}$ × 27.1441a

=> 220 = 27.1441 × a

=> a = $\dfrac{220}{27.1441}$

=> a = 8.10489 m/s²

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Acceleration of car is 8.1 m/s² (approx.)

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