Question

A car starts from rest and accelerates at 5 m/s through a distance of 22,5m.
How fast is it they going?
Hoe long did it take to cover 22,5 m ?​

Answer 1

Answer: This may help you

Explanation:

​Avg speed × total times = total distance

20×25=500

Since acceleration in the 1st interval is same as deceleration in the 3rd interval and deceleration is from the same velocity achieved after acceleration,

t 1=t 3

​s 1= 2 1 ×5t 1

​s 2=(5t 1)t 2

​s 3=(5t 1)×t 3− 2 1×5×t 1 2

=(5t 1)×t 1− 2 1×5×t 1 2

s 1+s 2+s 3=5t

1t 2+5t

1t 2⇒5t

1 2+5t

1 2=500−−−−1

2t 1+t 2

​=25−−−−2

Solving (1 ) and   (2) ⇒t 1=5,

t 2=15sec

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