Question

a car starts from rest and accelerates at a rate of 3m/s^2 for 10s. find its average velocity

Answer 1

Answer:

15 m/s

Explanation:

According to the given question,

u = initial velocity = 0 m/s

a = acceleration = 3 m/s^2

t = 10 sec

v = final velocity = ?

s = displacement = ?

And we are asked to find the average velocity.

We know,

• s = ut+1/2 at^2

Putting the values we get,

• s = 1/2 × 3× 100

• s = 150 m

We know,

• Avg. velocity = (total displacement)/(total time)

Putting the values we get

• Avg velocity = 150/10

• avg velocity =15 m/s

Thus avg. velocity is 15m/s .

Answer 2

Answer:

First know the terms!

a is the acceleration, which is given by $\frac{v-u}{t}$ u is the initial velocity

v is the final velocity

t is the time-period taken

Given,

a=$3ms^2$

u= 0 (as the car starts from rest)

v= unknown

t= 10 seconds

So, we need to find the average velocity of the car.

We know the formula,

v=u+at

Putting values in the formula

v=0+(3×10)

v=$30 ms^2$

So, the final velocity is 30$ms^2$

But we need to find the average velocity.

$Average Velocity=\frac{v+u}{2}$

$\implies \frac{30+0}{2}$

$\implies 15 ms^2\\ \therefore The\ average\ velocity\ of\ the\ car\ is\ 15\ \frac{m}{s}^2$