Question

A car starts from rest and accelerates uni formly over a time of 5.21 seconds for a distance of 110 m. Upton Chuck is riding the

Giant Drop at Great America. If Upton free falls for 2.6 seconds, what will be his final velocity and how far will he fall?

Answer 1

given,
d = 110 m       t = 5.21 s       v₁ = 0 m/s       a = ??

d = v₁*t + 0.5*a*t²

110 m = (0 m/s)*(5.21 s)+ 0.5*(a)*(5.21 s)²

110 m = (13.57 s²)*a

a = (110 m)/(13.57 s²)

a = 8.10 m/ s²

========================================================

given,

a = -9.8 m             t = 2.6 s                    vi = 0 m/s

d = vi*t + 0.5*a*t²

d = (0 m/s)*(2.60 s)+ 0.5*(-9.8 m/s²)*(2.60 s)²

d = -33.1 m 

vf = vi + a*t

vf = 0 + (-9.8 m/s²)*(2.60 s)

vf = -25.5 m/s 

Answer 2

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a = -9.8 m

t = 2.6 s

vi = 0 m/s

Find:

d = ??

vf = ??

d = vi*t + 0.5*a*t2

d = (0 m/s)*(2.60 s)+ 0.5*(-9.8 m/s2)*(2.60 s)2

d = -33.1 m (- indicates direction)

vf = vi + a*t

vf = 0 + (-9.8 m/s2)*(2.60 s)

vf = -25.5 m/s (- indicates direction)