Question

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110m.determine of acceleration of a car?

Answer 1

initial velocity=0
time(t)=5.21s
distance (s)=110m
acceleration(a)=?

formula:
s=(a*t*t)÷2
110=(a*5.21*5.21)÷2
110=(a*27.1441)÷2
110*2=a*27.1441
a=220÷27.1441
a=8.1048024638599490134245000810480 ms^-2