Question

a car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m dwtermine acceleration​

Answer 1

Answer:

using second eq of motion s=ut+1/2at

2

as u=0, a=

t

2

2s

=

5.21

2

2∗110

=8.10m/s

2

Explanation:

is your answer

Answer 2

Explanation:

$s = ut + \frac{1}{2} a {t}^{2} \\ s = distance \\ u = initial \: veocity \\ t \: = time \\ a = acceleration \\ 110 = \frac{1}{2} \times a \times( 5.21)^{2} \\8.1ms ^{ - 2}$