Question

a car starts from rest and accelerates uniformly to a speed of 72km/h over a distance of 500km calculate acceleration​

Answer 1

Answer:

• 5.184 km/h² is the required acceleration.

Explanation:

Given:-

• Initial velocity ,u = 0km/h

• Final velocity ,v = 72km/h

• Distance travelled ,s = 500km

To Find:-

• Acceleration ,a

Solution:-

As we know that Acceleration is defined as the rate of change of velocity at per unit time.

Using 3rd equation of motion

• v² = u² + 2as

Where,

• a denote acceleration
• v denote final velocity
• u denote initial velocity
• s denote distance

Substitute the value we get

→ 72² = 0² + 2×a × 500

→ 5184 = 0 + 1000 × a

→ 1000 × a = 5184

→ a = 5184/1000

→ a = 5.184 km/h²

• Hence, the acceleration of the car is 5.184 km/h².

Answer 2

Answer:

Given :-

• A car starts from rest and accelerates uniformly to a speed of 72 km/h over a distance of 500 km.

To Find :-

• What is the acceleration of a car.

Formula Used :-

✪ v² = u² + 2as ✪

where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• s = Distance covered

Solution :-

Given :

• Initial velocity = 0 m/s
• Final velocity = 72 km/h
• Distance covered = 500 km

According to the question by using the formula we get,

↦ (72)² = (0)² + 2(a)(500)

↦ 5184 = 0 + 2a(500)

↦ 5184 = 0 + 1000a

↦ 5184 = 1000a

↦ 5184/1000 = a

↦ 5.184 = a

➠ a = 5.184 m/s²

∴ The acceleration of a car is 5.184 m/s² .