Question

A car starts from rest and accelerates with 2 m/s2
for 10 seconds, After maintaining the velocity for
10 seconds, it comes to rest decelerating 1 m/s2
i) Draw the shape of V-t graph. ii) Find the maximum velocity attained and the total distance
travelled during the journey.

Answer 1

I.The velocity time graph of the  body is given below

Explanation:

• 2. for the first case the acceleration =2 metre / second ²

The time taken by the body in acceleration= 10s

So the velocity v= at ,since the body starts from rest and initial velocity is zero

V= 10x2= 20meter/ second.

• The distance during first part = 1/2 at²= 1/2 x 2x 10² = 100 meters.

During the second part , the distance covered,= S= vt , change the acceleration is zero

• S= 20x 10= 200meters

During the third part the distance covered= v²/2A , since the acceleration is negative here.

• So,the distance covered in 3rd party is equal to= 20²/ 2x1 = 200meter

• Hence the total distance covered by the car is equal to= 200+100+200= 500meter.

To know more,

Find the distance covered in 15 minutes by a car travelling at 40 km/hr

https://brainly.in/question/6391919

Answer 2

Answer:

500m

Explanation:

Please See the Answer In above Photo

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