Question

A car starts from rest and acquire the 54km/h in 2 minutes find:-
1. Acceleration
2. distance travelled by the car during this time assume the motion of car is uniform?

Answer 1

@
u= 0
v= 54km/h=(54*5/18)m/s= 15m/s
t= 2min= (2*60)sec= 120sec
______
1) v=u+at
→15=0+a*120
→15=120a
→15/120=a
→a=1/8
→a=0.125m/s²
Acceleration = 0.125m/s²
______
2) s=ut+1/2at²
→s=0*120+1/2*0.125*(120)²
→s=900m
Distance travelled = 900metre
@:-)

Answer 2

u = 0
v = 54km/h = 15m/s
t = 2 mins = 120 sec

1.) Acceleration-
By using 1st eq of motion
V= u +at
15 = 0 + a × 120
15 = 120a
15/120 = a
0.125 = a

2.) Distance travelled
By using second eq of motion
S= ut +1/2 at^2
s = 0×120 + 1/2×0.125 × 120 × 120
s = 1/2×.125×120×120
s = 900 m
Hope it helped!