a car starts from rest and acquires a velocity of 54 kilometre per hour in 2 metre find a) acceleration B) distance travelled by the car during this time assume motion of the car is uniformly
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Answered by
8
First I am assuming that 2m will be 2s,
Acceleration = Change in velocity /Time
=54-0/2/60=54/2/3600=54×3600/2=54×1800km/hr
Distance =ut+1/2at²=0×t+1/2at²=1/2at²=1/2×54×1800×4/(3600×3600)=54/3600km
Acceleration = Change in velocity /Time
=54-0/2/60=54/2/3600=54×3600/2=54×1800km/hr
Distance =ut+1/2at²=0×t+1/2at²=1/2at²=1/2×54×1800×4/(3600×3600)=54/3600km
Answered by
7
Given:
initial speed =u=0m/s
Velocity=54km/h=54*5/18=15m/s
time=assuming to be 2secs instead of 2meters
a=?
a=V-u/t
=15-0/2
a=7.5m/s²
S=ut+1/2at²
=0*2+(1/2)7.5*4
=75*4/20=15m
∴acceleration=7.5m/s²
Distance=15m
initial speed =u=0m/s
Velocity=54km/h=54*5/18=15m/s
time=assuming to be 2secs instead of 2meters
a=?
a=V-u/t
=15-0/2
a=7.5m/s²
S=ut+1/2at²
=0*2+(1/2)7.5*4
=75*4/20=15m
∴acceleration=7.5m/s²
Distance=15m
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