Question

a car starts from rest and acquires a velocity of 54 km per hour in 2 minutes.Find the acceleration and the distance travelled by a car during this time.assume that the acceleration of the car is uniform

Answer 1

A car From rest ➡️Accqires Velocity of 54 km/h

54 km/h➡️M/s=54×5/18=15m/s(v)
Car from rest=0m/s(u)

Time=2 minutes=120 seconds

Accerlation=(final Velocity-Intial Velocity/time)
=15-0/120
=15/120
Accerlation=0.125 m/s²

Distance Cover=(Final Velocty+Intial Velocity/2)×t
=(15+0/2)×120
=15/2×120
Distance cover=900 metres

Answer 2

u=0m/s
v=54km/h = 15m/s
t= 2min = 120 sec

acceleration = (v - u)/t
= (15 - 0)/120 m/s²
=15/120 m/s²
= 1/8 m/s²
= 0.125 m/s²


distance traveled (s) = ut + ½at²
s = 0×120 + ½ × ⅛ × (120)²
s = 900m