Question

A car starts from rest and aquires a velocity of 54km/hr in 2min find the acceleration and the distance travelled

Answer 1

Hiii...
Here is your answer..

Solution:-
Initial velocity(u)=0
Final velocity(v)
$= > \frac{15}{120} \\ = > .125$
=54km/h
$= > 54 \times \frac{5}{18} \\ = > 15$
=>15m/s
Time =2 min
$= > 2 \times 60 \\ = > 120seconds$

Now,
$acceleration = \frac{v - u}{t}$
$= > \frac{15 - 0}{120}$
$= > .125$
Therefore,
Acceleration=.125m/s

Now,
We have to find Distance,we will find it by using equation,that is,
$s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 \times 120 + \frac{1}{2}\times .125 \times {(120)}^{2}$
$s = 0 + \frac{1}{2} \times .125 \times 14400 \\ s = 0 + .125 \times 7200 \\ s = 900$
Hence,
Distance travelled=900m

Hope it helps uh...✌️✌️✌️

Answer 2

0.125m/s2 is accelaration