.A car starts from rest and attains a velocity of 10 m/s in 10 sec. The driver applies a break and slows down the car to 5 m/s in 10 sec. Find the acceleration of the car in both the cases.
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Answer:
V=at
⇒8=a10
⇒a=0.8m/s
2
V
2
=U
2
+2as
⇒U=8
2
+2×a64
⇒a=
2×64
−64
=−0.5m/s
2
Distance travelled= Area of graph
⇒584=
2
1
×10×8+8×t
1
+
2
1
×16×8
⇒584=40+8t
1
+64
⇒8t
1
=480
⇒t
1
=60
Total time= 10+60+16=86s
Explanation:
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