Question

If x + y + 2 = 0 then write the value of x3 + y3 + 8​

Answer 1

Answer:Given x+y+2=0,then

x3+y3+8=(x)3+(y)3+(2)3=0

=>We know if a+b+c=0,then

a3+b3+c3=3abc

=>x3+y3+(2)3=3.x.y.2

=>x3+y3+8=6xy

Step-by-step explanation:

Answer 2

Answer:

We know,

if

$a + b + c = 0$

then

$a ^3 + b^3 + c^3 = 3abc$

Because

$a^3 + b^3 + c^3 = 1 \div 2(a + b + c) \: (a ^{2} + b^{2} + c^{2} - ab - bc - ca)$

Now when

$a + b + c = 0$

Then

$a^3 + b^3 + c ^3 = 3abc$

Here

$x + y + 2 = 0$

So

$x^3 + y^3 + 2^3 = 3xy(2)$

$x ^3 + y ^3 + 8 = 6xy$

hope it's help you