A car starts from rest and attains a velocity of 20m/s in 5s. Calculate the distance during this
time.
Answers
Answer: 50 m
Explanation:
Given : u = 0 m/s
: v = 20 m/s
: T = 5 s
To find : S = ?
We know that
a = v - u/ t
a = 20 - 0 / 5
a = 4 m/s²
Now
By 2 equation of motion
S = ut + 1/2 at²
S = 0 × 5 + 1/2 × 4 × 5²
S = 0 + 1/2 × 4 × 25
S = 1 × 2 × 25
S = 50 m
Hope It helps you
Thanks
Explanation:
Given : A car starts from rest and attains a velocity of 20m/s in 5s.
To Find : the distance during this time.
Solution:
u = 0
v = 20 m/s
t = 5 s
v= u + at
=> 20 = 0 + a(5)
=> a = 4 m/s²
S = ut + (1/2)at²
=> S = 0 + (1/2)(4)* 5²
=> S = 2 * 25
=> S = 50 m
the distance during this time = 50 m
Another method :
S =t * (v + u)/2
=> S = 5 * (20 + 0)/2
=> S = 50 m
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