Question

The slope of straight line passing throught (5,8)
and (-3,4) is​

Answer 1

$\huge{\bf{\green{\mathfrak{Question:-}}}}$

$\bullet{\mapsto}$ The slope of straight line passing throught (5,8) and (- 3,4) is ?

$\huge {\bf{\orange{\mathfrak{Answer:-}}}}$

$\bullet{\leadsto} \: \textsf{Given points are (5,8) and (- 3,4).}$

$\bullet{\leadsto} \: \textsf{We know that,}$

$\bullet{\leadsto} \: \sf Slope \: of \: a \: line \: = \: m \: = \: \dfrac{y_{2} \: - \: y_{1}}{x_{2} \: - \: x_{1}}$

$\bullet{\leadsto} \: \sf \dfrac{y_{2} \: - \: y_{1}}{x_{2} \: - \: x_{1}}$

$\bullet{\leadsto} \: \sf \dfrac{4 \: - \: 8}{- \: 3 \: - \: 5}$

$\bullet{\leadsto} \: \sf \dfrac{- \: 4}{- \: 8}$

$\bullet{\leadsto} \: \sf \dfrac{4}{8}$

$\bullet{\leadsto} \: \boxed{\sf \dfrac{1}{2}}$

$\huge{\bf{\red{\mathfrak{Conclusion:-}}}}$

$\bullet{\mapsto} \: \boxed{\therefore{\sf Slope \: of \: the \: line \: = \: \dfrac{1}{2} \: = \: 0.5.}}$

Answer 2

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GIVEN :-

(5,8) (-3,4)

SLOPE OF LINE "-

$m = \frac{y²-y¹}{x²-x¹}$

SOLUTION :-

$\frac{Y²-y¹}{x² -x¹} \\➣ \frac{4-8}{-3-5} \\➣ \frac{-4}{-8} \\ Cut - to - in \frac{-4}{-8} \\\\So, \frac{4}{8} \\ ‣ \frac{1}{2}$

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Hope It Helps