Question

A car starts from rest and covers 400m in 20sec. Find the acceleration of the car.​

Answer 1

Answer:

2 m/s^2

Explanation:

According to the given question,

u = initial velocity = 0 m/s

s = displacement = 400 m

t = time = 20 s

a = acceleration = ?

And we are asked to find the acceleration.

We know,

• s =ut+1/2 at^2

(Putting the values we get)

• 400 = 0 + 1/2 ×a× 400

• 400 = (400/2)×a

• 1 = 1/2 × a

• a = 2 m/s^2 ans.

So the car have an acceleration of 2 m/s^2.

Answer 2

Answer:

2 m / sec²

Explanation:

Given :

Initial velocity ( u ) = 0 m / sec .

Distance ( s ) = 400 m

Time ( t ) = 20 sec

We have to find acceleration :

From second equation of motion we have :

s = u t + 1 / 2 a t²

Putting values here

400 = 0 × 20 + 1 / 2 × a × 20 × 20

400 = a × 10 × 20

200 a = 400

a = 2 m / sec² .

Thus the acceleration of car is 2 m / sec² .