Question

A car starts from rest and gains velocity 30 m/s in 10 seconds. Find the distance travelled by that car during that time. *

Answer 1

Answer:

V=at

⇒8=a10

⇒a=0.8m/s  

2

 

V  

2

=U  

2

+2as

⇒U=8  

2

+2×a64

⇒a=  

2×64

−64

​  

=−0.5m/s  

2

 

Distance travelled= Area of graph

⇒584=  

2

1

​  

×10×8+8×t  

1

+  

2

1

​  

×16×8

⇒584=40+8t  

1

+64

⇒8t  

1

=480

⇒t  

1

=60

Total time= 10+60+16=86s

Explanation:

Answer 2

Explanation:

GIVEN;

INITIAL VELOCITY = 0 M/S

FINAL VELOCITY = 30 M/S

TIME TAKEN BY CAR. = 10 SECONDS.

SOLUTION;

BY USING ,FIRST OF EQUATION OF MOTION;

V = U + AT

A = V - U / T

30 =. 0 + A (10)

A =. 30 - 0 / 10

A. = 3 M/S^ 2

BY USING SECOND EQUATION OF MOTION ;

S = UT + 1/2 AT^2

S =. (0)(10) + 1/2 × 3 × 10 × 10

S =. 0 +. 3 × 50

S. =. 150 M .

SO THE DISTANCE TRAVELLED BY CAR IN 10 SECONDS IS 150 M.

THANKS FRIEND, HOPE IT HELPS.