Question

Factorise : 20 + 13x^2 + x^3 + 32x​

Answer 1

Step-by-step explanation:

20 + 13x^2 + x^3 + 32x

Let p(x) = x3 + 13x2 + 32x + 20.

p(-1) = -1 + 13 - 32 + 20 = -33 + 33 = 0.

Therefore (x + 1) is a factor of p(x).

On dividing p(x) by (x + 1) we get.

p(x) (x + 1) = x2 + 12x + 20.

Thus,

x3 + 13x2 + 32x + 20 = (x + 1)(x2 + 12x + 20)

= (x + 1) (x2 + 10x + 2x + 20)

MARK AS BRAINLIEST...

Answer 2

x3 + 13x2 + 32x + 20 = (x + 1)(x2 + 12x + 20) = (x + 1) (x2 + 10x + 2x + 20) = (x + 1)[x(x + 10) + 2(x + 10)] = (x + 1) (x +2) (x + 10)