Question

A car starts from rest and move along the x axis with constant acceleration 9m/s^2 for 6 sec .if it then continues with constant velocity, what distance will the car cover in 10sec since it starts from the rest

Answer 1

Answer:-

• Acceleration=a=9m/s^2
• Time=t=10s
• Initial velocity=u=0m/s
• Distance=s

According to 2nd equation of kinematics

$\boxed{\sf s=ut+\dfrac{1}{2}at^2}$

$\\ \sf\longmapsto s=0(10)+\dfrac{1}{2}\times 9\times 10^2$

$\\ \sf\longmapsto s=\dfrac{9\times 100}{2}$

$\\ \sf\longmapsto s=\dfrac{900}{2}$

$\\ \sf\longmapsto s=450m$