a car starts from rest and moves along the x-axis with constant acceleration 5m/s^2 for 8 second. If it then continues with constant velocity, what distance will the car cover in 12 sec since it started from rest?
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a= 5m/s^2, u= 0, t= 8sec
a = (v-u)/t
5 = v/8
v = 5*8
v = 40m/s.
In 12sec the car speed will be 60m/s.
Distance = area covered under v vs t graph.
= 2(l+b)
= 2(60+12)
= 2(72)
= 144m
a = (v-u)/t
5 = v/8
v = 5*8
v = 40m/s.
In 12sec the car speed will be 60m/s.
Distance = area covered under v vs t graph.
= 2(l+b)
= 2(60+12)
= 2(72)
= 144m
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