Question

A car starts from rest and moves along the X-axis with constant acceleration 5 ms for 8 s. If it then continues with constant velocity. What distance will the car cover in 12 s, since it started from rest?
3 points
1) 320 m
2) 420 m
3) 160 m
4) None of These

Answer 1

V=u+at

v=0+5m/s^2*8

v=40m/s

constant velocity=40m/s

distance covered in the first 8 sec = S=1/2a*t^2=160m.

distance covered in the last 4 sec=const. speed*time=40m/s*4=160m

total distance covered in 12 sec=160+160=320m ans.

ans=320m

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Answer 2

Explanation:

1)

I hope this may help you..

Thanks...