Question

A car starts from rest and moves along the x-axis with constant acceleration 5 m/s2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?
Please fast its very very urgent​

Answer 1

Answer:

Given: A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2 for 8 seconds

To find: what distance will the car cover in 12 seconds since it started from rest

Solution:

We know that,

s = ut + 1/2at²

But given that, the initial velocity is zero. Therefore, the distance covered by the car in first 8 seconds is

s = 0 + 1/2 × 5 × 8²

s = 160 metres

Therefore, the velocity attained at the end of 8 seconds is:

v = u + at

v = 0 + 5 × 8

= 40m/s

Therefore, since the car has moved with constant velocity from 8th second to 12 second, the distance traveled is

s = v × t

= 40 × 4 = 160 metre

Therefore, the total distance traveled is

160m + 160m = 320metre

Hope It Helps