Question

A car starts from rest and moves along the xaxis with constant acceleration of 5m/t 8 seconds since it started from rest

Answer 1

Hello!

When the acceleration a is constant, the speed V is equal to V(t)=V_0+at, where V_0 is the initial speed. The distance traveled is D(t)=V_0 t+(a t^2)/2.

The final speed is V_1=V_0t+at=0+5*8=40(m/s). The distance of accelerated motion is 0+(5*8^2)/2=160(m), the distance of constant speed motion is V_1*(12-8)=40*4=160(m). So the total distance is 320m.

Answer 2

Answer:

Total Distance if 320 m