Question

A car with a speed of 50kmph can be stopped by brakes after at least 6m.Uf the same car is moving at a speed of 100kmph the minimum stopping distance is

Answer 1

Initial velocity, u = 50 km/h = 50 × (5/18) = 250/18 m/s

Final velocity, v = 0

Distance travelled before coming to rest, s = 6 m

Using, v2 = u2 + 2as

= a = -u2/(2s)

= a = -16.075 m/s2

Again,

u = 100 km/h = 500/18 m/s

v = 0

a = -16.075 m/s2

Now, v2 = u2 + 2as

= s = -u2/(2a) = 24 m

Answer 2

Answer:

V2 - U2 = 2ab

= U2 /(2s)

= a = 16075

: v2 - u2 = 2 ab

= Us/(2s) = 24 m

= 24 m