a car starts from rest and moves through a distance S0 with constant acceleration f,after which it continues moving with uniform velocity for time t and then decelerates at the rate of f/2 to come to rest,if total distance travelled is 10S0,then
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Answer:
If t
2
be the time for which the car decelerates at the rate f/2 to come rest, the distance traveled in time t
2
is given by,
0
2
−v
1
2
=2(−f/2)s
3
(using formula v
2
−u
2
=2as)
or s
3
=(ft
1
)
2
/f=ft
1
2
...(3)
using (1), s
3
=2s
1
=2s
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