![3y - 5 \6 \4 + 1 = 2y - 1 \3 \3 + 5 3y - 5 \6 \4 + 1 = 2y - 1 \3 \3 + 5](https://tex.z-dn.net/?f=3y+-+5+%5C6++%5C4+%2B+1+%3D+2y+-+1+%5C3+%5C3+%2B+5)
Answers
Answered by
0
Step-by-step explanation:
3y-5+1= 2y-1+5
3y-2y= (-1)+ 5+5-1
y= 10-1-1
y= 9-1
y=8
Answered by
0
3y - 2y = 5 - 1 - 1 + 5
y = 4-1+5
y = 8
Hope it helps you
Pls mark me as brainliest
y = 4-1+5
y = 8
Hope it helps you
Pls mark me as brainliest
Similar questions