Physics, asked by dineshkotangale, 1 year ago

A car starts from rest and moves with a constant accleration of 0.2ms-2 . What will be its speed after 2 minutes ? What will be the distance covered by a car during this period?

Answers

Answered by Priyaverma1234
0
u=0
t=120sec
a=0.2msec-2
v=u+at
v=24m per second
you can find distance by second equation of motion ut+1/2at square

samirbirua6738p9l4pt: answer will be 12
Priyaverma1234: no...it is correct
samirbirua6738p9l4pt: whats the answer
Priyaverma1234: answer will be 24m per second and the distance is 1440 m
Answered by maharshiguin100
0
accelaration  : a=0.2  ms-2
time              :  t=2 min = 120 sec
initial speed  : u=0 m/s(rest)
final speed   : v=?
distance     :  s=?
  
v=u+at
  =0+0.2*120
  =24 m/s
s=ut+1/2 at^2
   =0*120+1/2 * 0.2 * 120*120
   =1/2 * 0.2 * 120 *120 
   = 1440 m 

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