A car starts from rest and moves with a constant accleration of 0.2ms-2 . What will be its speed after 2 minutes ? What will be the distance covered by a car during this period?
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u=0
t=120sec
a=0.2msec-2
v=u+at
v=24m per second
you can find distance by second equation of motion ut+1/2at square
t=120sec
a=0.2msec-2
v=u+at
v=24m per second
you can find distance by second equation of motion ut+1/2at square
samirbirua6738p9l4pt:
answer will be 12
Answered by
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accelaration : a=0.2 ms-2
time : t=2 min = 120 sec
initial speed : u=0 m/s(rest)
final speed : v=?
distance : s=?
v=u+at
=0+0.2*120
=24 m/s
s=ut+1/2 at^2
=0*120+1/2 * 0.2 * 120*120
=1/2 * 0.2 * 120 *120
= 1440 m
I hope that this helps u :)
Mark it as brainliest if it has benefitted u .
time : t=2 min = 120 sec
initial speed : u=0 m/s(rest)
final speed : v=?
distance : s=?
v=u+at
=0+0.2*120
=24 m/s
s=ut+1/2 at^2
=0*120+1/2 * 0.2 * 120*120
=1/2 * 0.2 * 120 *120
= 1440 m
I hope that this helps u :)
Mark it as brainliest if it has benefitted u .
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