Question

A jar contains blue and green marbles. The number of green marbles is 5 more than twice the number of blue marbles. If probability of drawing a blue marbles at rand is 2\7,how many blue and green marbles are there in jar

Answer 1

Let the blue marbles be x . 
Then green marbles are 2x + 5 

Total no. of marbles = 3x+5 
so , x/3x+5 =2/7 
By cross-multiplication , 
we get , 7x = 6x+10 
i.e. x =10 (blue marbles )

Hence , blue marbles =10 
             green marbles = 2(10) +5 = 20 +5 = 25

Answer 2

Let the blue marbles be x . 

Then green marbles are 2x + 5 

Total no. of marbles = 3x+5 

so , x/3x+5 =2/7 

By cross-multiplication , 

we get , 7x = 6x+10 

i.e. x =10 (blue marbles )

Hence , blue marbles =10 

             green marbles = 2(10) +5 = 20 +5 = 25

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